ISWC · Musical Work

T-060674484-6

Minas Tirith

31 recordings

Last verified: November 3, 2026

The ISWC for “Minas Tirith” is T-060674484-6. ISWCs are ISO 15707 identifiers managed by CISAC; they identify the underlying song — its melody, lyrics, and arrangement — rather than any single recording. One composition can have many recordings (ISRCs). This work has 31 known recordings (ISRCs) indexed on Credits.fm.

Format

TPrefix

060674484Work number

6Check digit

Prefix:: "T" = musical work; "W" = work in progress.
Work number:: 9-digit unique work number assigned by CISAC.
Check digit:: ISO 7064 Mod 11-2 check digit that validates the rest of the code.

Credit Chain

ISRC31 recordings

ISWCMinas Tirith

Previously known as

T-060682086-3

What other identifiers does this connect to?

Songwriters/Publishers (IPI)

00043047410 00061632792

Creative Contributors (ISNI)

0000 0001 2123 2327

SourcesCISACMLCMusicBrainzNotes CreditsMusicBrainz5 sources

Verified on

CISAC ISWC registry search

Identifier Graph

What is ISWC T-060674484-6?

T-060674484-6 is an International Standard Musical Work Code (ISWC) that uniquely identifies the musical composition “Minas Tirith”. ISWCs are defined by ISO 15707 and managed by CISAC. Unlike ISRCs which identify recordings, an ISWC identifies the underlying song — the melody, lyrics, and arrangement.

This work has 31 recordings (ISRCs) associated with it. Each recording represents a distinct version — such as the original, a remix, a live performance, or a cover — that shares the same underlying composition.

T-060674484-6

Format

Previously known as

What other identifiers does this connect to?

Verified on

People also ask

What is ISWC T-060674484-6?

T-060674484-6

Format

Previously known as

What other identifiers does this connect to?

Which releases contain this work? (9)

Recordings (31)

Who are the artists on this work?

Verified on

People also ask

What is ISWC T-060674484-6?

Which releases contain this work? (9)

Recordings (31)

Who are the artists on this work?